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comp / comp.os.linux.advocacy / Simple challenge VII for the simpleton Feeb

SubjectAuthor
* Simple challenge VII for the simpleton FeebDFS
`- Re: Simple challenge VII for the simpleton FeebDFS

1
Subject: Simple challenge VII for the simpleton Feeb
From: DFS
Newsgroups: comp.os.linux.advocacy
Date: Sat, 15 Jun 2024 11:43 UTC
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From: nospam@dfs.com (DFS)
Subject: Simple challenge VII for the simpleton Feeb
Newsgroups: comp.os.linux.advocacy
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You recently claimed "There are *no* competent C programmers here
(except little ol' me)."

It's long past time for you to begin trying to prove your programming
competency (you NEVER have, in any language).

Write one C routine that will compute the 3 quartiles of any dataset of
positive integers. Quartiles subdivide the datasets into 4ths by median.

Here are some random datasets to work from.

N = 20:
3 9 9 12 17 22 29 29 33 35 36 37 40 44 46 49 50 51 55 57

N = 21:
3 3 4 4 4 7 8 9 13 17 30 32 34 36 38 42 43 43 45 48 54

N = 30:
6 12 13 17 19 20 20 20 22 23 29 32 34 40 41 42 44 46 48 50 61 64 66 68
69 72 73

N = 31:
6 10 10 15 19 21 21 31 36 42 44 48 50 50 51 52 58 62 68 69 70 70 72 76
81 82 82 84 84 92 93

Use this method:
Q1 = median of lower half not including Q2
Q2 = median of dataset
Q3 = median of upper half not including Q2

Example
1 2 3 4 5 6 7 8 9 10 11

Q1 = 3
Q2 = 6
Q3 = 9

I've already written such code, in C and python. And I posted both to
clc, so don't cheat and plagiarize it from there or elsewhere as you
often do.

See you NEVER, fraudulent lying asshole.

Subject: Re: Simple challenge VII for the simpleton Feeb
From: DFS
Newsgroups: comp.os.linux.advocacy
Date: Sun, 16 Jun 2024 15:29 UTC
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Subject: Re: Simple challenge VII for the simpleton Feeb
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On 6/15/2024 7:43 AM, DFS wrote:
>
> You recently claimed "There are *no* competent C programmers here
> (except little ol' me)."
>
> It's long past time for you to begin trying to prove your programming
> competency (you NEVER have, in any language).
>
> Write one C routine that will compute the 3 quartiles of any dataset of
> positive integers.  Quartiles subdivide the datasets into 4ths by median.
>
> Here are some random datasets to work from.
>
> N = 20:
> 3 9 9 12 17 22 29 29 33 35 36 37 40 44 46 49 50 51 55 57
>
> N = 21:
> 3 3 4 4 4 7 8 9 13 17 30 32 34 36 38 42 43 43 45 48 54
>
> N = 30:
> 6 12 13 17 19 20 20 20 22 23 29 32 34 40 41 42 44 46 48 50 61 64 66 68
> 69 72 73
>
> N = 31:
> 6 10 10 15 19 21 21 31 36 42 44 48 50 50 51 52 58 62 68 69 70 70 72 76
> 81 82 82 84 84 92 93
>
>
> Use this method:
> Q1 = median of lower half not including Q2
> Q2 = median of dataset
> Q3 = median of upper half not including Q2
>
> Example
> 1 2 3 4 5 6 7 8 9 10 11
>
> Q1 = 3
> Q2 = 6
> Q3 = 9
>
>
> I've already written such code, in C and python.  And I posted both to
> clc, so don't cheat and plagiarize it from there or elsewhere as you
> often do.
>
> See you NEVER, fraudulent lying asshole.

crickets.

Geez... it's hard to believe Feeb ran away from a simple coding
challenge like he did umpteen times before...

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