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comp / comp.lang.python / Re: Flubbed it in the second interation through the string: range error... HOW?

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* Re: Flubbed it in the second interation through the string: range error... HOW?MRAB
`- Re: Flubbed it in the second interation through the string: range error... HOW?Stefan Ram

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Subject: Re: Flubbed it in the second interation through the string: range error... HOW?
From: MRAB
Newsgroups: comp.lang.python
Date: Wed, 29 May 2024 14:59 UTC
References: 1 2 3 4
Path: eternal-september.org!news.eternal-september.org!feeder3.eternal-september.org!fu-berlin.de!uni-berlin.de!not-for-mail
From: python@mrabarnett.plus.com (MRAB)
Newsgroups: comp.lang.python
Subject: Re: Flubbed it in the second interation through the string: range
error... HOW?
Date: Wed, 29 May 2024 15:59:50 +0100
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On 2024-05-29 15:32, Thomas Passin via Python-list wrote:
> On 5/29/2024 8:55 AM, Kevin M. Wilson wrote:
>> Please recall, I said the format for the email failed to retain the
>> proper indents.
>> I'll attach a picture of the code!
>> Purpose; to uppercase every other letter in a string.
>>
>> Thanks all, KMW
>
> Simpler is good, and readability is good. For a simple conversion that
> has a little touch of generality:
>
> s1 = 'this is a test'
> def convert(i, ch):
> return ch.upper() if i % 2 else ch
>
> result = ''.join([convert(i, ch) for i, ch in enumerate(s1)])
> print(result) # tHiS Is a tEsT
>
[snip]
Small mistake there. The original code converted to uppercase on even
indexes, whereas your code does it on odd ones.

> However, this has a weakness: what to do about spaces. Should they be
> counted among the characters to be uppercased? or should they not be
> included in the count of the alternation? If you want to uppercase
> every other letter that is not a space, things become a little more
> complicated. And then do you want this to apply to all whitespace or
> only spaces?
>
> If you want to skip changing spaces, then you need to track the state of
> converted characters in some way. It would probably be easier (and more
> readable) to use a "for x in t:" construction:
>
> def convert(convert_this, ch):
> """Convert character ch if convert_this is True.
> Don't convert spaces.
> """
> if convert_this:
> if ch == ' ':
> return (convert_this, ch)
> elif convert_this:
> return (False, ch.upper())
> return (True, ch)
>
> convert_next = False
> result = ''
> for ch in s1:
> convert_next, ch = convert(convert_next, ch)
> result += ch
> print(result) # tHiS Is A TeSt
>
> There could be even more complications if you allow non-ascii characters
> but you were asking about processing character by character so I won't
> get into that.
>
> (You haven't specified the problem in enough detail to answer questions
> like those).
>
[snip]

Subject: Re: Flubbed it in the second interation through the string: range error... HOW?
From: Stefan Ram
Newsgroups: comp.lang.python
Organization: Stefan Ram
Date: Wed, 29 May 2024 18:09 UTC
References: 1 2 3 4 5
Path: eternal-september.org!news.eternal-september.org!feeder3.eternal-september.org!fu-berlin.de!uni-berlin.de!not-for-mail
From: ram@zedat.fu-berlin.de (Stefan Ram)
Newsgroups: comp.lang.python
Subject: Re: Flubbed it in the second interation through the string: range error... HOW?
Date: 29 May 2024 18:09:07 GMT
Organization: Stefan Ram
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Expires: 1 Feb 2025 11:59:58 GMT
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MRAB <python@mrabarnett.plus.com> wrote or quoted:
>Small mistake there. The original code converted to uppercase on even
>indexes, whereas your code does it on odd ones.

Here follows my humble effort.

import doctest

def alternate_uppercase( s ):
"""
Alternates the case of alphabetic characters in a given string.

Args:
s (str): The input string.

Returns:
str: The string with alternating uppercase and lowercase letters.

Examples:
>>> alternate_uppercase( 'Python is awesome!' )
'PyThOn Is AwEsOmE!'

>>> alternate_uppercase( 'ab,c,,d,,,e,,,,f' )
'Ab,C,,d,,,E,,,,f'

>>> alternate_uppercase( '' )
''
"""
result =[ None ]* len( s )
letter_count = 0
for char_pos, char in enumerate( s ):
if char.isalpha():
result[ char_pos ]=\
( char.lower if letter_count%2 else char.upper )()
letter_count += 1
else:
result[ char_pos ]= char
return ''.join( result )

doctest.testmod()

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